fix 修复 三方登录查询用户信息参数错误问题

This commit is contained in:
疯狂的狮子Li
2023-07-31 17:16:43 +08:00
parent 7888b0e857
commit d2f61fc241
3 changed files with 30 additions and 1 deletions

View File

@@ -62,6 +62,26 @@ public class RemoteUserServiceImpl implements RemoteUserService {
return buildLoginUser(userMapper.selectUserByUserName(username));
}
@Override
public LoginUser getUserInfo(Long userId, String tenantId) throws UserException {
SysUser sysUser = userMapper.selectOne(new LambdaQueryWrapper<SysUser>()
.select(SysUser::getUserName, SysUser::getStatus)
.eq(TenantHelper.isEnable(), SysUser::getTenantId, tenantId)
.eq(SysUser::getUserId, userId));
if (ObjectUtil.isNull(sysUser)) {
throw new UserException("user.not.exists", "");
}
if (UserStatus.DISABLE.getCode().equals(sysUser.getStatus())) {
throw new UserException("user.blocked", sysUser.getUserName());
}
// 框架登录不限制从什么表查询 只要最终构建出 LoginUser 即可
// 此处可根据登录用户的数据不同 自行创建 loginUser 属性不够用继承扩展就行了
if (TenantHelper.isEnable()) {
return buildLoginUser(userMapper.selectTenantUserByUserName(sysUser.getUserName(), tenantId));
}
return buildLoginUser(userMapper.selectUserByUserName(sysUser.getUserName()));
}
@Override
public LoginUser getUserInfoByPhonenumber(String phonenumber, String tenantId) throws UserException {
SysUser sysUser = userMapper.selectOne(new LambdaQueryWrapper<SysUser>()